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NEET Thermodynamics Signs: Physics vs Chem — Learnzy

Never confuse work done in Physics vs Chemistry again. The definitive First Law sign convention comparison table for NEET droppers with zero +/- sign errors.
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Direct Answer • The Fix

In Chemistry: Delta U = q + w, work done by system on surroundings is NEGATIVE (w = -P Delta V). In Physics: Delta U = Q - W, work done by system on surroundings is POSITIVE (W = +P Delta V). In both subjects, Delta U and heat signs are identical: heat absorbed is positive (+), heat released is negative (-).

Every NEET dropper has experienced this exact moment of mental paralysis:

On Tuesday morning, you revise Class 11 Physics Heat and Thermodynamics. You solve a problem where an ideal gas expands and pushes a piston. Your Physics teacher tells you: "Work done by the gas during expansion is positive ($W = +P\Delta V$), so internal energy drops: $\Delta U = Q - W$." You solve 20 questions, get them all right, and feel confident.

On Wednesday evening, you open Class 11 Physical Chemistry Thermodynamics. You encounter the exact same ideal gas expanding against external pressure. Your Chemistry teacher writes: "Work done by the system during expansion is negative ($w = -P\Delta V$), so the First Law is $\Delta U = q + w$."

Your brain shorts out. Why are the signs completely inverted? Is work positive or negative? Which formula do you apply on Sunday?

Seedha Faisla: In NEET Physical Chemistry, the thermodynamic system (the reacting gas) is the primary frame of reference: work done on the system during compression is positive ($w > 0$), work done by the system during expansion is negative ($w < 0$), and the First Law of Thermodynamics is written as $\Delta U = q + w$. In NEET Physics, the mechanical engine delivering output to the surroundings is the primary frame of reference: work done by the gas during expansion is positive ($W > 0$), work done on the gas is negative ($W < 0$), and the First Law is written as $\Delta U = Q - W$. Both formulations yield the exact same physical reality and identical internal energy change $\Delta U$. On exam day between 2:00 PM and 5:00 PM, identify the section first: use $w = -P_{\text{ext}}\Delta V$ for Chemistry questions and $W = +P\Delta V$ for Physics questions to eliminate recurring sign errors.

Why Do Thermodynamics Sign Conventions Clash Between Physics and Chemistry?

The physics and chemistry equations look contradictory only because they adopt two different points of view. Think of it like a bank transaction:

Parameter Chemistry (IUPAC Perspective) Physics (Engine Perspective) Action Rule for NEET
Primary Reference Frame The System (the reacting gas inside container). The Engine / Surroundings (work delivered). Chemistry measures gas energy; Physics measures engine work.
Heat Absorbed by System $+q$ (Energy enters system) $+Q$ (Heat supplied to gas) Both subjects use positive sign for heat entering.
Heat Released by System $-q$ (Energy exits system) $-Q$ (Heat rejected by gas) Both subjects use negative sign for heat leaving.
Work Done on Gas (Compression) $w > 0$ (System gains mechanical energy) $W < 0$ (External agent does work on gas) In Chemistry, compression increases energy: $+w$.
Work Done by Gas (Expansion) $w < 0$ (System spends energy on surroundings) $W > 0$ (Useful mechanical work delivered) In Physics, output work is positive: $+W$.
First Law Formulation $\Delta U = q + w$ where $w = -P_{\text{ext}}\Delta V$ $\Delta U = Q - W$ where $W = +P_{\text{ext}}\Delta V$ Both yield identical numerical change $\Delta U$.

Notice the underlying mathematical truth: both equations yield the exact same change in internal energy ($\Delta U$)!

When a gas expands, it loses internal energy to push the surroundings.

  • In Chemistry: $w$ is negative, so $\Delta U = q + (-|w|) = q - |w|$.
  • In Physics: $W$ is positive, so $\Delta U = Q - (+|W|) = Q - |W|$.

The physical reality is identical. Only the algebraic bookkeeping changes.

What Is the Core Difference Between the System and Engine Perspectives?

In nineteenth-century industrial engineering, steam engines were built to pump water out of coal mines. Engineers cared exclusively about the useful mechanical work ($W$) the engine delivered to the wheels and pistons. Hence, work produced by the engine was marked positive ($W > 0$).

Chemists, however, care about chemical reactions occurring inside a closed flask. Under IUPAC rules, the reaction mixture is the system. If the reaction pushes a piston upward, the chemical system loses internal energy to the environment, meaning the system has performed work ($w < 0$).

When solving numericals, never debate philosophy. Treat the sign convention purely as a notation rule tied to the subject section.

How Do You Apply the 3 Golden Rules in the NEET Exam Hall?

To ensure your hand never hesitates between 2:00 PM and 5:00 PM on test day, lock in these three operational rules:

  1. Check the Question Paper Section First:
  • If the question appears in the Chemistry Section (Questions 46–90): Strictly write $\Delta U = q + w$ and $w = -P_{\text{ext}}\Delta V$. Work done by gas expansion is negative.
  • If the question appears in the Physics Section (Questions 1–45): Strictly write $\Delta U = Q - W$ and $W = P\Delta V$. Work done by gas expansion is positive.
  1. Watch for the Free Expansion Trap:
  2. In an insulated container ($q = 0$) expanding into a vacuum ($P_{\text{ext}} = 0$):

  • $w = 0$ (no resistance to push against).
  • $q = 0$ (adiabatic).
  • Therefore, $\Delta U = 0$ and $\Delta T = 0$ (for ideal gases).
  • This holds true in both Physics and Chemistry. Free expansion does zero work.

  1. Isothermal vs Adiabatic Work Magnitudes:
  2. For a given expansion from $V_1$ to $V_2$:

$$|w_{\text{isothermal}}| > |w_{\text{adiabatic}}|$$

Why? Because in an isothermal expansion, heat continuously enters the system to maintain temperature and pressure. In an adiabatic expansion, the system cools as it works, causing pressure to drop faster.

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Deep Dive: Physical Chemistry Formulas for NEET — Learnzy →

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Frequently Asked Questions

Direct Answers • High-Yield

Why is work done by an expanding gas negative in Chemistry but positive in Physics?

Chemistry follows IUPAC convention, where the gas inside the container is the system. Expanding against external pressure costs the system internal energy, so work done by the system is negative ($w < 0$). Physics follows classic thermodynamic engineering, where the useful work delivered by the engine to the surroundings is defined as positive ($W > 0$).

Does internal energy change differ when using Chemistry vs Physics First Law equations?

No. The calculated change in internal energy ($\Delta U$) is mathematically identical in both subjects. In Chemistry, $\Delta U = q + w$ with negative expansion work ($w = -P\Delta V$). In Physics, $\Delta U = Q - W$ with positive expansion work ($W = +P\Delta V$). Both simplify to $\Delta U = q - P\Delta V$.

What is the sign convention for work done in an isothermal free expansion?

In free expansion against a vacuum, external pressure ($P_{\text{ext}}$) is zero. Consequently, work done is exactly zero in both Chemistry and Physics ($w = 0$ and $W = 0$). Because the process is isothermal ($\Delta T = 0$), internal energy change ($\Delta U$) is also zero for an ideal gas.

Which equation should I use if a NEET question does not specify the subject?

NEET questions are divided into clear Physics and Chemistry sections. If a question is printed in the Physics section, write $\Delta U = Q - W$. If it is printed in the Chemistry section, write $\Delta U = q + w$. Recognizing the section origin prevents mixing sign conventions.